problema solutie acid azotic

[dumitru]

3,6g carbon se trateaza cu o solutie de acid azotic de concentratie 63%.calculeaza numarul total de moli de gaze ce rezulta.

[justakid]

C + 4HNO3 -> CO2 + 4NO2 + 2H2O

12g carbon (1 mol) => 1 mol CO2 si 4 moli NO2=5 moli gaze
3,6g carbon.....(5*3,6)/12=1,5 moli gaze

1 mol de gaz ocupa 22,4L in conditii normale (p=1 atm, t=0 grade celsius) => 1,5*22,4=33,6L gaze